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Exercise 7.1 Question 1: Find the distance between the following pairs of points: (i) (2, 3), (4, 1) (ii) (-5, 7), (-1, 3) (iii) (a, b), (-a, -b) Answer: (i) Distance between the two points is given by (sqrt {(x_1-x_2)^2+(y_1-y_2)^2}) Therefore, dustance between (2, 3) and (4, 1) is given by (l=sqrt{(2-4)^2+(3-1)^2=sqrt{(-2)^2+(2)^2}}) (=sqrt{4+4}=sqrt8=2sqrt2) (ii) Distance between […]

NCERT Solutions for class-10 Science chapter 1 Chemical Reactions and Equations is prepared by senior and renown teachers of EduAid primary focus while solving science questions of class-10 is NCERT textbook, read the theory of this chapter and try to understand the meaning and then after start writing the questions given in class-10 NCERT textbook

NCERT Solutions for Class 10 Chemistry Chapter 1 – “Chemical Reactions and Equations” is curated by senior and experienced teachers of EduAid. Before answering the questions of Chapter 1. This chapter delves into the fascinating world of chemical reactions, helping students understand and master the principles of balancing chemical equations and different types of reactions. Here are the

Exercise 5.1 Question 1: In which of the following situations, does the list of numbers involved make as arithmetic progression and why? (i) The taxi fare after each km when the fare is Rs 15 for the first km and Rs 8 for each additional km. (ii) The amount of air present in a cylinder

Exercise 4.1 Question 1: Check whether the following are quadratic equations: (i) ((x_1)^2=2(x-3)) (ii) (x^2-2x=(-2)(3-x)) (iii) ((x-2)(x+1)=(x-1)(x+3)) (iv) ((x-3)(2x+1)=x(x+5)) (v) ((2x-1)(x-3)=(x+5)(x-1)) (vi) (x^2+3x+1=(x-2)^2) (vii) ((x+2)^3=2x(x^2-1)) (viii) (x^34x^2-x+1=(x-2)^2) Answer:  (i) ((x+1)^2=2(x-3)) (⇒x^2+2x+1=2x-6) (⇒x^2+7=0) It is of the form (ax^2+bx+c=0) Hence, the given equation is a quadratic equation. (ii) (x^2-2x(-2)(3-x)) (⇒x^2-2x=-6+2x) (⇒x^2-4x+6=0) It is of the form

Exercise 3.1 Question 1: Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situation algebraically and graphically. Answer: Let the present age of Aftab be (x).

Exercise 2.1 Question 1: The graphs of (y = p(x)) are given in following figure, for some polynomials (p(x)). Find the number of zeroes of (p(x)), in each case. (i)   Answer:  (i) The number of zeroes is (0) as the graph does not cut the (x)-axis at any point. (ii) The number of zeroes

Exercise 1.1 Question 1: Use Euclid’s division algorithm to find the (HCF) of: (i) (135) and (225)                                   (ii) (196) and (38220)                        (iii) (867) and (225) Answer: (i) (135) and (225) Since (225 > 135), we apply the division lemma to (225) and (135)  to obtain (225 = 135times 1 + 90) Since remainder (90 ≠

NCERT Solutions for class-16 Science chapter 16 “Management of  Natural  Resources” is curated by senior and experienced teachers of EduAid. Before answering the questions of Chapter 16 , read the theory of the chapter multiple times and get a clear understanding of the concepts included in the chapter. Here are the answers of the questions included in the