Chapter 5: Periodic Classification of Elements
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Intext Questions (Page 81)
12 marks
Did Dobereiner's triads also exist in the columns of Newlands' octaves? Compare and find out.
Answer: Yes, some triads of Dobereiner were found in Newlands' octaves. For example, the triad Li, Na, K had atomic masses 7, 23, 39 respectively. In Newlands' classification, Li (1st element), Na (8th element), K (15th element) fell into the same column (every 8th element), showing similar properties.
22 marks
What were the limitations of Dobereiner's classification?
Answer: (i) It could only classify a few elements into triads. (ii) All known elements could not be grouped into triads. (iii) In some triads, the atomic mass of the middle element was not exactly the arithmetic mean of the other two.
32 marks
What were the limitations of Newlands' law of octaves?
Answer: (i) It was applicable only up to calcium. After calcium, every 8th element did not have similar properties. (ii) Newlands placed two elements in the same slot (e.g., Co and Ni). (iii) It did not leave any space for new elements. (iv) It placed iron with elements of different properties.
Intext Questions (Page 85)
43 marks
Use Mendeleev's periodic table to answer the following: (a) What are the groups into which elements are classified? (b) How many groups and periods are in Mendeleev's periodic table? (c) What are the properties of elements based on?
Answer: (a) Groups – vertical columns containing elements with similar properties. (b) 8 groups (I to VIII) and 7 periods (horizontal rows). Some groups were subdivided into A and B sub-groups. (c) Mendeleev's classification was based on atomic mass and similarity in chemical properties.
52 marks
Why could no fixed position be given to hydrogen in Mendeleev's periodic table?
Answer: Hydrogen has properties similar to both alkali metals (Group I) and halogens (Group VII). It can lose an electron to form H⁺ like metals, or gain an electron to form H⁻ like halogens. This dual behaviour made its position uncertain.
Intext Questions (Page 90)
63 marks
How does the electronic configuration of an atom relate to its position in the modern periodic table?
Answer: The period number corresponds to the number of electron shells (principal quantum number). The group number for main group elements equals the number of valence electrons. Thus, electronic configuration determines both group and period.
72 marks
In the modern periodic table, which are the metals among the first ten elements?
Answer: Among the first ten elements (H to Ne), the metals are: Lithium (Li), Beryllium (Be). Boron (B) is a metalloid. Sodium (Na) is 11th, not in first ten.
82 marks
By considering their position in the periodic table, which one of the following elements would you expect to have the maximum metallic character: Ga, Ge, As, Se, Be?
Answer: Be (beryllium). Metallic character decreases along a period (from left to right) and increases down a group. Be is in group 2, period 2. Among given, Ga (group 13) is less metallic than Be. So Be has the maximum metallic character.
NCERT Exercise Questions (Page 91)
Ex 11 mark
Which of the following statements is not a correct statement about the trends when going from left to right across the periods of the periodic table? (a) The elements become less metallic in nature. (b) The number of valence electrons increases. (c) The atoms lose their electrons more easily. (d) The oxides become more acidic.
Answer: (c) The atoms lose their electrons more easily – this is false; across a period, ionization energy increases, so losing electrons becomes harder.
Ex 21 mark
Element X forms a chloride with formula XCl₂, which is a solid with high melting point. X would be likely to be in the same group of the periodic table as: (a) Na (b) Mg (c) Al (d) Si
Answer: (b) Mg – since XCl₂ indicates X has valency 2 (group 2 metals like Mg, Ca).
Ex 31 mark
Which of the following elements will form an acidic oxide? (a) An element with atomic number 7 (b) An element with atomic number 3 (c) An element with atomic number 12 (d) An element with atomic number 19
Answer: (a) Element with atomic number 7 (Nitrogen) – non-metals form acidic oxides. Atomic number 3 (Li) and 12 (Mg) and 19 (K) are metals, form basic oxides.
Ex 43 marks
An element has an atomic number 12. (a) What is its electronic configuration? (b) To which period and group does it belong? (c) Is it a metal or non-metal? (d) What is the valency of this element? (e) Write the formula of its chloride and oxide.
Answer: (a) Electronic configuration: 2, 8, 2 (1s²2s²2p⁶3s²). (b) Period – 3; Group – 2 (alkaline earth metal). (c) Metal. (d) Valency = 2. (e) Chloride: MgCl₂, Oxide: MgO.
Ex 53 marks
An element X (atomic number 17) reacts with an element Y (atomic number 20) to form a compound. (a) Write the position of these elements in the periodic table. (b) Write the formula of the compound. (c) Write the nature of the compound.
Answer: (a) X (Cl, atomic number 17) – Group 17, Period 3; Y (Ca, atomic number 20) – Group 2, Period 4. (b) Compound: CaCl₂ (calcium chloride). (c) Ionic compound (salt).
Ex 62 marks
How do the following properties change in a group and a period? (a) Atomic radius (b) Metallic character (c) Ionization energy (d) Electronegativity.
Answer: Across a period: atomic radius decreases, metallic character decreases, ionization energy increases, electronegativity increases. Down a group: atomic radius increases, metallic character increases, ionization energy decreases, electronegativity decreases (for main group elements).
Ex 73 marks
Write the formula of the following compounds: (i) Sodium sulphate (ii) Aluminium chloride (iii) Calcium hydroxide (iv) Magnesium bicarbonate (v) Potassium phosphate.
Answer: (i) Na₂SO₄ (ii) AlCl₃ (iii) Ca(OH)₂ (iv) Mg(HCO₃)₂ (v) K₃PO₄.
Ex 83 marks
How do you calculate the valency of an element from its electronic configuration? What is the valency of Mg (atomic number 12)?
Answer: Valency is the number of electrons lost, gained, or shared to achieve stable octet (or duplet). For Mg (2,8,2), it can lose 2 electrons to attain octet, so valency = 2.
Ex 92 marks
Compare and contrast the arrangement of elements in Mendeleev's periodic table and the modern periodic table.
Answer: Mendeleev's table arranged elements by increasing atomic mass, with groups for similar properties. Modern table arranges by increasing atomic number. Mendeleev's had gaps for undiscovered elements; modern has no gaps. Modern has 18 groups (vs 8 groups in Mendeleev's). Modern table explains periodicity through electronic configuration.
Additional Important Questions
A12 marks
What is the modern periodic law? Who proposed it?
Answer: Modern periodic law states: "The physical and chemical properties of elements are periodic functions of their atomic numbers." It was proposed by Henry Moseley (1913).
A22 marks
Why did Mendeleev leave gaps in his periodic table?
Answer: Mendeleev left gaps for elements that were not yet discovered, predicting their properties. Later, elements like gallium (eka-aluminium), scandium (eka-boron), and germanium (eka-silicon) were discovered and filled those gaps.
A32 marks
What are the advantages of the modern periodic table over Mendeleev's table?
Answer: (i) Based on atomic number, not atomic mass, so no anomalies (like K and Ar). (ii) Separates metals and non-metals clearly. (iii) Explains periodicity via electronic configuration. (iv) Positions of isotopes are not an issue.
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