NCERT Solutions for Maths Class 9 Chapter 12

CHAPTER 12

Exercise 12.1:

Question 1: A survey conducted by an organisation for the cause of illness and death among the women between the ages 15−44 (in years) worldwide, found the following figures (in %):

S. No.CausesFemale Fatality rate (%)
1Repriductive health conditions31.8
2Neuropsychiatric conditions24.4
3Injuries12.4
4Cardiovascular conditions4.3
5Respiratory conditions4.1
6Other causes22.0

(i) Represent the information given above graphically.

Answer: 

 

Graph

(ii) Which condition is the major cause of women’s ill health and death worldwide?
Anaswer: Reproductive Health is a major cause of mortality.
(iii) Try to find out, with the help of your teacher, any two factors which play a major role in the cause in (ii) above being the major cause.
Answer:  Lack of knowledge and diet
Question 2: The following data on the number of girls (to the nearest ten) per thousand boys in different sections of Indian society is given below:

SectionNumber of girls per thousand boys
Scheduled caste (SC)940
Schedule tribe (ST)970
Non SC/ST920
Backward districts950
Non-backward districts920
Rural930
Urban910

(i) Represent the information above by a bar graph.

Answer: 

Graph

(ii) In the classroom discuss what conclusions can be arrived at from the graph.
Answer:  Number of girls are higher in ST. Number of girls are same in SC/ST and Non- Backward districts.

Question 3: Given below are the seats won by different political parties in the polling outcome of a state assembly elections:

Politacl PartyABCDEF
Seats Won755537291037

(i) Draw a bar graph to represent the polling results.

Answer:

Graph

(ii) Which political paerty won the maximum number of seats?

Answer: Party A won the seats

Question 4: The length of \(40\) leaves of a plant are measured correct to one millimetre, and the obtained data is represented in the following table:

S. No.Length (in mm)Number of leaves
1118-1263
2127-1355
3136-1449
4145-15312
5154-1625
6163-1714
7172-1802

(i) Draw a hitogram to represent the given data.

Answer: We have to represent length of leaves of \(x\) axis and number of leaves in \(y\) axis. Its scale of \(1\) unit\(=2\) leaves.

Now the class interval is in irregular interval so we have to make it regular, we can observe that difference of upper limit and lower limit is 1 and half of 1 is 0.5

LengthNumber of Leaves
117.5-126.53
126.5-135.55
135.5-144.59
144.5-153.512
153.5-162.55
162.5-171.54
171.5-180.52

Graph

(ii) Is there any other suitable graphical representation for the same data?
Answer: Other suitable graph will be frequency polygon
(iii) Is it correct to conclude that the maximum number of leaves are 153 mm long? Why?
Answer:  No, as maximum number of leaves 12 has length ranging from 144.5-153.5, so all length cannot be 153mm

Question 5: The following table gives the life times of neon lamps:

Life time (in hours)Number of lamps

300-400

400-500

500-600

600-700

700-800

800-900

900-1000

14

56

60

86

74

62

48

(i) Represent the given information with the help of a histogram.
Answer: 

Graph

(ii) How many lamps have a lifetime of more than 700 hours?
Answer: 75 lamps are there in 700 hours.

Question 6: The following table gives the distribution of students of two sections according to the mark obtained by them:

Section ASection B
0-1030-105
10-20910-2019
20-301720-3019
30-101230-4010
40-50940-501

Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections

Answer: 

For section A

ClassesClass-MarksFrequency
0-1053
10-20159
20-302517
30-403512
40-50459

For section B

ClassesClass-MarksFrequency
0-1055
10-201519
20-302515
30-403510
40-50451

Graph

Question 7: The runs scored by two teams A and B on the first 60 balls in a cricket match are given below:

Number of ballsTeam ATeam B
1-625
7-1216
13-1882
19-24910
25-3045
31-3656
37-4263
43-48104
49-5468
55-60210

Represent the data of both the teams on the same graph by frequency polygons.
[Hint: First make the class intervals continuous.]
Answer: As it can be seen data is not continuous, and the difference in upper limit and lower limit is 1, so to make class interval continuous 0.5 needed to be added in each limit.

Class \(=\frac{Upper\space Limit+Lower\space Limit}{3}\)

Number of BallsClass MarkTeam ATeam B
0.5-6.53.525
6.5-12.59.516
12.5-18.515.582
18.5-24.521.5910
24.5-30.527.545
30.5-36.533.556
36.5-42.539.563
42.5-48.545.5104
48.5-54.551.568
54.5-60.557.5210

Question 8: A random survey of the number of children of various age groups playing in park was found as follows:

Age (in years)Number of Children
1-25
2-33
3-56
5-712
7-109
10-1510
15-174

Draw a histogram to represent the data above.
Answer: Here class size will be 1

Age in YearsNumber of children FrequencyWidth of class

Length of rectangle

\(\frac{Number\space of\space children}{width\space of \space class}\times class\space size\)

1-251

5

2-331

3

3-562

3

5-7122

6

7-1093

3

10-15105

2

15-1742

2

Graph

Question 9: 100 surnames were randomly picked up from a local telephone directory and a frequency distribution of the number of letters in the English alphabet in the surnames was found as follows:
(i) Draw a histogram to depict the given information.
Answer:
Here we have to draw modified table with class size 2

Number of lettersNumber surname FrequencyWidth of class

Length of rectangle 

\(\frac{Surname\space of \space students}{Width\space of\space class}\times Class\space size\)

1-463

4

4-6302

30

6-8442

44

8-12164

8

12-2048

1

(ii) Write the class interval in which the maximum number of surname lie.
Answer:
6-8 is the class interval where maximum sir names lies.

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