CHAPTER 8
Journey Inside the Atom
Questions & Solutions | Exploration | Class 9 Science
Think It Over Page 160
Think It Over
Are atoms the smallest indivisible particles? Why do electrons not fall into the nucleus even though they are attracted to protons in it? Why did scientists keep modifying atomic models?
Solution
Atoms are divisible and contain subatomic particles (electrons, protons, neutrons). Electrons do not fall into the nucleus because they revolve in fixed energy levels (Bohr's model). Scientists modified atomic models as new experimental evidence (like gold foil experiment, discovery of neutrons) emerged.
Pause and Ponder
Page 163 (Q1)
Suppose you made up your own 'atom', as Thomson described, using clay for the positive charge and small beads for the electrons spread through it. What will happen if: (i) the positive charge on the clay is lesser than the total negative charge of the beads? (ii) by mistake, the clay itself carries a bit of negative charge? Would your model still represent a neutral atom?
Solution
(i) The atom would have a net negative charge (anion). (ii) The atom would have a net negative charge. No, it would not represent a neutral atom because total positive and negative charges would not be equal.
Page 163 (Q2)
Could an orange or a lemon, which also contain seeds inside soft pulp, be a good comparison? In what ways does it match Thomson's idea and where does it fall short?
Solution
An orange matches Thomson's model as seeds (electrons) are embedded in pulp (positive charge). It falls short because Thomson's model had a uniform positive sphere, while an orange has compartments and the positive charge is not uniformly distributed.
Page 163 (Q3)
Why did Thomson conclude that electrons are present in all atoms?
Solution
Cathode rays (electrons) were produced regardless of the gas used in the tube or the material of the cathode, showing that electrons are a fundamental component of all atoms.
Page 164 (Q4)
What do you think would happen if α-particles were replaced with negatively charged particles in Rutherford's gold foil experiment?
Solution
Negatively charged particles would be attracted to the positive nucleus, so they would be deflected differently (towards the nucleus) instead of being repelled.
Page 164 (Q5)
Rutherford found that a few α-particles bounced back sharply. How does this single surprising result completely rule out Thomson's 'plum pudding model' of the atom?
Solution
In Thomson's model, positive charge is spread uniformly, so α-particles would pass through with little deflection. Sharp backward scattering requires a concentrated positive charge (nucleus) — impossible in Thomson's model.
Page 164 (Q6)
If you could ask Rutherford one question about his work, what would it be?
Solution
Answers may vary. Example: "How did you explain the stability of the atom with electrons orbiting the nucleus?" (Rutherford's model could not explain stability.)
Page 165 (Q7)
Assertion (A): Rutherford concluded that most of the mass of an atom is concentrated in a small region at the centre called the nucleus. Reason (R): According to Thomson's model, electrons are embedded in a uniformly distributed positive charge sphere. Choose the correct option: (i) Both A and R are true, and R is the correct explanation of A. (ii) Both A and R are true, but R is not the correct explanation of A. (iii) A is true, but R is false. (iv) A is false, but R is true.
Solution
Option (ii) is correct. Both statements are true, but R (Thomson's model) does not explain Rutherford's conclusion.
Page 169 (Q8)
Imagine you are a scientist who has discovered a new element. Name this element after yourself and justify that the symbol you have chosen follows the IUPAC rules.
Solution
Example: Element name: Sharmaum. Symbol: Sh (first letter capital, second letter lowercase). This follows IUPAC rules.
Page 169 (Q9)
What problems could arise if every scientist used different symbols for the same element?
Solution
It would cause confusion, miscommunication, and errors in scientific research, publications, and global collaboration.
Page 170 (Q10)
An atom with an atomic number of 26 has 56 nucleons. Find out its number of electrons, protons and neutrons.
Solution
Protons = atomic number = 26. Electrons = 26 (neutral atom). Neutrons = mass number - atomic number = 56 - 26 = 30.
Page 170 (Q11)
The nucleus of an atom contains 20 protons. If its mass number is 41, find the number of neutrons in it.
Solution
Neutrons = mass number - protons = 41 - 20 = 21.
Page 170 (Q12)
An atom has 18 neutrons and an atomic number of 17. What is its mass number?
Solution
Mass number = protons + neutrons = 17 + 18 = 35.
Page 170 (Q13)
An atom ²³A has 11 electrons. Find the number of neutrons in it.
Solution
Protons = electrons = 11 (neutral atom). Mass number = 23. Neutrons = 23 - 11 = 12.
Page 172 (Q14)
Identify the number of electrons in the outermost shell of the following elements: (i) ¹²₆C (ii) ¹⁹₉F (iii) ²⁸₁₄Si
Solution
(i) Carbon: electronic config 2,4 → valence electrons = 4. (ii) Fluorine: 2,7 → valence electrons = 7. (iii) Silicon: 2,8,4 → valence electrons = 4.
Page 172 (Q15)
Write the electronic configuration of the elements having atomic numbers 12, 16 and 18.
Solution
Atomic number 12 (Mg): 2,8,2. Atomic number 16 (S): 2,8,6. Atomic number 18 (Ar): 2,8,8.
Page 172 (Q16)
Solve this riddle: I am an atom with a mass number of 23 and 11 protons. I am a soft metal and react vigorously with water. Who am I and how many neutrons do I have? You can also create one such riddle.
Solution
Sodium (Na). Neutrons = 23 - 11 = 12. Example riddle: "I have 17 protons and 18 neutrons. I am a greenish-yellow gas used for disinfection. Who am I?" (Chlorine-35).
Page 176 (Q17)
Two different atoms have 11 protons each, but one has 12 neutrons, and the other has 13 neutrons. How do their atomic numbers and mass numbers compare? Are they the same element or different elements?
Solution
Atomic numbers are same (11). Mass numbers are 23 and 24. They are the same element (sodium) — isotopes.
Page 176 (Q18)
If a bromine atom is available in the form of, say two isotopes, ⁷⁸₃₅Br (49.7%) and ⁸¹₃₅Br (50.3%), calculate the average atomic mass of the bromine atom.
Solution
Average = (78 × 0.497) + (81 × 0.503) = 38.766 + 40.743 = 79.509 u.
Ready to Go Beyond
Page 164
Can you calculate how many atoms would be needed to make a sheet of paper that is 0.1 mm thick, like the one in your textbook? If the diameter of one atom is about 10⁻¹⁰ m and the sheet is 0.1 mm (10⁻⁴ m) thick, number of atoms ≈ (10⁻⁴ m) ÷ (10⁻¹⁰ m) = 10⁶. That is about one million atoms need to be stacked together! When these atoms come together, they form the solid materials we see and touch. What feels like a simple sheet is actually a vast assembly of tiny building blocks, all neatly arranged. It's amazing how the unseen atomic world shapes everything we see and use every day!
Solution
About 1 million atoms stacked make a 0.1 mm thick sheet of paper.
Page 167
The discovery of the neutron opened a new era in atomic physics. Neutrons, being uncharged, can easily penetrate nuclei, leading to breakthroughs, such as the creation of artificial radioactive elements and the splitting of uranium atoms. This gave birth to the 'atomic age', allowing the development of both nuclear power and nuclear weapons.
Solution
Neutrons can penetrate nuclei because they have no charge, enabling nuclear reactions like fission and the creation of radioactive isotopes.
Page 174
Atoms are too tiny to be weighed in kilograms or grams like everyday objects. Just as it is easier to weigh a grain of wheat in milligrams rather than kilograms, scientists use a special unit called the unified atomic mass unit (u) to measure the mass of atoms. This is because a kilogram is too large for such small particles. Earlier, atomic mass was expressed in atomic mass unit (abbreviated as 'amu').
Solution
1 u = 1/12th the mass of a carbon-12 atom ≈ 1.66 × 10⁻²⁷ kg.
Page 176
Electron microscopes, such as Scanning Tunnelling Microscopes (STMs) and Transmission Electron Microscopes (TEMs) can produce images of materials with atomic-level details. STMs mainly study surfaces (Fig.8.15), while TEMs reveal how atoms are arranged inside very thin samples.
Solution
STMs image surfaces at atomic resolution; TEMs image internal structure of thin samples.
Threads of Curiosity
Page 166
Why are Bohr's shells called K, L, M, N... and not A, B, C, D? The naming came from early X-ray experiments by the physicist, Charles Barkla, who called the first observed X-ray line K. He didn't start naming from A to leave room for possible discovery of a series earlier than the K series, although none were ever found. Bohr adopted the same notation for atomic shells.
Solution
Bohr's shells are named K, L, M, N... based on X-ray spectroscopy naming convention, where K was the first observed X-ray line.
Page 167
Lighter atoms often have an equal number of protons and neutrons (like carbon with six each or oxygen with eight each). However, as atoms get heavier, their nuclei have many more neutrons than protons. Iron has 26 protons and 30 neutrons, and by the time we reach uranium, the nucleus has 92 protons and 146 neutrons. You may wonder that since all the protons with like charges are squished together in a nucleus why do they not push each other away? Think of it this way—every proton inside the nucleus repels every other proton because they all carry positive charge. Neutrons being neutral help reduce this repulsion by intervening and increasing the distance between protons, and also by strengthening the force, called the nuclear force, that binds all particles together. So, heavier atoms need many more neutrons to hold everything in the nucleus tightly bound.
Solution
Neutrons reduce proton-proton repulsion and contribute to the strong nuclear force, stabilizing the nucleus. Heavier nuclei require more neutrons for stability.
Page 174
Some isotopes have special properties that are useful in various fields. Some of the applications of isotopes are: ²³⁵U is used as fuel in nuclear reactors. ⁶⁰Co is used in radiation treatment for cancer. ¹³¹I is used to treat goitre and thyroid cancer. ¹⁴C is used in archaeology to determine the age of ancient fossils and artefacts.
Solution
Isotopes have important applications in medicine (cancer treatment), energy (nuclear fuel), and archaeology (carbon dating).
Meet a Scientist
Page 162 - J.J. Thomson
J. J. Thomson's most significant discovery was that of the electron, the first subatomic particle to be identified and a part of every atom. He received the Nobel Prize in Physics in 1906 for his studies of the electrical conductivity of gases. This research led him to discover electrons. As the head of the famous Cavendish Laboratory in Cambridge, he guided and inspired many scientists, including Ernest Rutherford.
Solution
J.J. Thomson discovered the electron through cathode ray experiments and proposed the plum pudding model of the atom.
Page 165 - Ernest Rutherford
Ernest Rutherford worked with J. J. Thomson and later became known as the Father of Nuclear Physics. He discovered the atomic nucleus and explained how some elements naturally break down, for which he won the 1908 Nobel Prize in Chemistry. In 1911, he proposed the nuclear model of the atom. His portrait now appears on New Zealand's $100 banknote.
Solution
Rutherford discovered the nucleus through the gold foil experiment and proposed the nuclear model of the atom.
Page 166 - Niels Bohr
Niels Bohr was a professor of physics at Copenhagen University, Denmark. He was curious about how atoms exist because the old models could not explain why electrons stay around the nucleus without collapsing. His explanation of the atomic structure provided more clarity. Niels Bohr received the Nobel Prize in 1922, for his work on the structure of the atom.
Solution
Bohr proposed that electrons revolve in fixed energy levels (shells) and do not lose energy while in these orbits, explaining atomic stability.
Page 167 - James Chadwick
James Chadwick, working at the Cavendish Laboratory at the University of Cambridge, solved a key puzzle in 1932, when he discovered the neutron. This breakthrough explained atomic mass and earned him the Nobel Prize in Physics in 1935. The neutron immediately transformed research, enabling scientists to probe nuclear secrets, and sparked a chain of discoveries in understanding and harnessing atomic energy.
Solution
James Chadwick discovered the neutron, a neutral subatomic particle in the nucleus, explaining atomic mass discrepancies.
Page 176 - Homi Jehangir Bhabha
Homi Jehangir Bhabha was an Indian physicist. He is known as the father of the Indian nuclear programme. He made a pioneering contribution to the development of atomic energy in India. He established key institutions like the Tata Institute of Fundamental Research (TIFR) and the Bhabha Atomic Research Centre (BARC), for peaceful uses of atomic energy to generate electricity, support agriculture, and advanced medical treatments.
Solution
Homi J. Bhabha founded TIFR and BARC and pioneered India's nuclear energy programme for peaceful applications.
India's Scientific Contributions Page 168
India's Scientific Contributions
The Bhabha Atomic Research Centre (BARC, Fig. 8.8), Mumbai, leads advanced neutron-scattering experiments using reactors, such as Dhruva. This has revealed key insights into materials like superconductors, battery electrodes, and drug molecules, helping develop better medicines, energy storage, and industrial alloys right here in India. Research and explore more about Dhruva!
Solution
BARC's Dhruva reactor enables neutron-scattering experiments for materials research, contributing to advancements in medicine, energy storage, and industrial alloys.
Think as a Scientist Page 164
Think as a Scientist
Observe Fig. 8.4 of the gold foil experiment. Predict the observations you would expect if the gold foil in the experiment were made thicker. Also, draw a simple diagram to show the observations you expect. Hint: Compare thin foil vs thick foil. How does the thickness affect the chances of hitting a nucleus?
Solution
With thicker foil, more α-particles would be deflected or absorbed because the chance of hitting a nucleus increases. Fewer particles would pass straight through.
What if... Page 167
What if...
an atom had no empty space? How would this have affected the size of various objects?
Solution
If atoms had no empty space, objects would be extremely dense and tiny. All matter would be compressed to the size of atomic nuclei, making everyday objects unimaginably small and dense.
END-OF-CHAPTER EXERCISES Pages 178-180
1.
Choose the correct options and explain the reason for the correct and incorrect options in the context of Ernest Rutherford's gold foil experiment: (i) The experiment clearly showed the existence of neutrons in the nucleus. (ii) The results disproved the plum pudding model and led to the idea of a nucleus at the centre of the atom. (iii) The large deflection of a few alpha particles indicated that most of the mass of the atom and positive charge are packed into a tiny centre. (iv) The way alpha particles were deflected showed that electrons move around the nucleus.
Solution
Options (ii) and (iii) are correct. (i) is incorrect — neutrons were discovered later by Chadwick. (iv) is incorrect — the experiment did not provide information about electron motion.
2.
Which of the following statements are correct or incorrect according to the Bohr's atomic model? Give a reason for each statement. (i) Electrons lose energy while moving in fixed orbits and slowly fall into the nucleus. (ii) Electrons can exist anywhere around the nucleus with no fixed energy. (iii) Electrons revolve around the nucleus in orbits of fixed energy without losing energy. (iv) Electrons can be found between energy levels as they move around the nucleus.
Solution
(i) Incorrect — electrons in fixed orbits do not lose energy. (ii) Incorrect — electrons exist only in fixed energy levels. (iii) Correct. (iv) Incorrect — electrons cannot exist between energy levels.
3.
The composition of the nuclei of three atomic species X, Y, and Z are given as follows: X: protons 18, neutrons 19; Y: protons 17, neutrons 18; Z: protons 17, neutrons 20. Explain the relation between the following: (i) Y and Z (ii) Z and X
Solution
(i) Y and Z are isotopes (same atomic number 17, different mass numbers 35 and 37). (ii) Z and X are isobars (same mass number 37, different atomic numbers 17 and 18).
4.
What conclusion did Rutherford draw about the position and characteristics of the atom's positively charged part based on the few alpha particles that bounced back or were deflected at large angles in the gold foil experiment?
Solution
Rutherford concluded that the positive charge is concentrated in a tiny, dense nucleus at the centre of the atom, containing most of the atom's mass.
5.
Explain and arrange the following statements in the correct chronological order to show how atomic models have evolved over time. (i) Bohr's model proposed that electrons move in fixed orbits around the nucleus, each with a definite energy. (ii) Thomson's model depicted the atom as a 'plum pudding' with electrons embedded in a sphere of positive charge. (iii) Rutherford's model proposed that atoms have a dense central nucleus. (iv) Dalton's model described atoms as indivisible particles.
Solution
Correct order: (iv) Dalton → (ii) Thomson → (iii) Rutherford → (i) Bohr.
6.
Electrons move around the nucleus in orbits. Why do they not fly away from the atom? Explain what keeps them attracted to the nucleus.
Solution
Electrostatic attraction between positively charged protons and negatively charged electrons keeps electrons bound to the atom.
7.
Assertion (A): The discovery of subatomic particles helped in understanding the atomic structure. Reason (R): The number of electrons is equal to the number of protons in an atom. Choose the correct option: (i) Both A and R are true, and R is the correct explanation of A. (ii) Both A and R are true, but R is not the correct explanation of A. (iii) A is true, but R is false. (iv) A is false, but R is true.
Solution
Option (ii) is correct. Both statements are true, but R does not explain why discovery of subatomic particles helped understanding atomic structure.
8.
Magnesium is essential for many biological processes, including muscle contraction. For an atom of magnesium with a mass number of 24 and atomic number 12, determine the number of (i) protons, (ii) neutrons, (iii) electrons, and also illustrate the arrangement of electrons in a magnesium atom.
Solution
(i) Protons = 12, (ii) Neutrons = 12, (iii) Electrons = 12. Electronic configuration: 2,8,2.
9.
Find the following information for the elements shown in Fig. 8.17: (i) Name of the element (ii) Symbol (iii) Total number of electrons (iv) Number of valence electrons (v) Valency of the element (vi) Number of protons (vii) Atomic number
Solution
(a) Lithium (Li): electrons=3, valence=1, valency=1, protons=3, atomic number=3. (b) Nitrogen (N): electrons=7, valence=5, valency=3, protons=7, atomic number=7. (c) Aluminium (Al): electrons=13, valence=3, valency=3, protons=13, atomic number=13. (d) Fluorine (F): electrons=9, valence=7, valency=1, protons=9, atomic number=9.
10.
Both Rutherford's and Bohr's models have electrons orbiting the nucleus. Why did Rutherford's model fail to explain atomic stability, while Bohr's model succeeded?
Solution
Rutherford's model could not explain why electrons do not spiral into the nucleus (accelerating charged particles lose energy). Bohr proposed that electrons revolve in fixed energy levels and do not lose energy while in these orbits, thus explaining stability.
11.
An atom ⁷⁰X has 31 electrons. How many neutrons are there in its nucleus?
Solution
Protons = electrons = 31. Mass number = 70. Neutrons = 70 - 31 = 39.
12.
An atom has 79 protons and a mass number of 197. Calculate (i) the number of neutrons, and (ii) the number of electrons.
Solution
(i) Neutrons = 197 - 79 = 118. (ii) Electrons = 79 (neutral atom).
13.
Complete the Table 8.5: Atomic number 5, Mass number 11, Neutrons 6, Protons 5, Electrons 5, Name Boron. Atomic number 7, Mass number 14, Neutrons 7, Protons 7, Electrons 7, Name Nitrogen. Atomic number 12, Mass number 24, Neutrons 12, Protons 12, Electrons 12, Name Magnesium. Atomic number 15, Mass number 31, Neutrons 16, Protons 15, Electrons 15, Name Phosphorus. Atomic number 1, Mass number 1, Neutrons 0, Protons 1, Electrons 1, Name Hydrogen.
Solution
Table completed as above.
14.
Aman was discussing the structure of atom with his classmates. During the discussion, he learnt that an element X has a mass number of 35 and contains 18 neutrons. Based on this information, answer the following questions: (i) How many electrons and protons does element X have? (ii) What is its atomic number? (iii) Identify the element X. (iv) Write its electronic configuration. (v) How many valence electrons does it have? (vi) What will be the mass number if two neutrons are added to its nucleus? (vii) What will be the relation of X with the new atom?
Solution
(i) Protons = 35 - 18 = 17, Electrons = 17. (ii) Atomic number = 17. (iii) Chlorine (Cl). (iv) Electronic configuration: 2,8,7. (v) Valence electrons = 7. (vi) Mass number = 37. (vii) They are isotopes of chlorine.
15.
In an atom, there are 12 protons and 12 neutrons in the nucleus. Now, imagine that all the electrons are replaced with some hypothetical particles that have the same charge as electrons but are 500 times heavier. What effect will this replacement have on the atom's: (i) Atomic number (ii) Atomic mass (iii) Mass number (iv) Overall charge
Solution
(i) Atomic number remains 12 (same number of protons). (ii) Atomic mass increases (electrons contribute mass now). (iii) Mass number remains same (mass number counts only nucleons). (iv) Overall charge remains neutral (same number of positive and negative charges).
Chapter Summary
- Atoms are the building blocks of matter.
- J.J. Thomson proposed the plum pudding model (electrons embedded in positive sphere).
- Rutherford's gold foil experiment showed atoms have a small, dense, positively charged nucleus.
- Bohr's model: electrons revolve in fixed energy levels (shells) — K, L, M, N...
- Subatomic particles: electron (negative), proton (positive), neutron (neutral).
- Atomic number (Z) = number of protons. Mass number (A) = protons + neutrons.
- Isotopes: same atomic number, different mass numbers. Isobars: same mass number, different atomic numbers.
- Electronic configuration: 2n² rule for maximum electrons per shell. Valence electrons determine valency.
- Valency = number of electrons gained, lost, or shared to achieve stable octet.
Also Get
Class 9- NCERT- Science Solⁿ.
Class 9-NCERT- English Solⁿ
Class 9-NCERT- Maths
Solⁿ
Class 9-NCERT- Social Science Solⁿ
Class 9 CBSE - SYLLABUS
📚 Exploration | Class 9 Science | NCERT
Chapter 8: Journey Inside the Atom — All Questions with Solutions
Chapter 8: Journey Inside the Atom — All Questions with Solutions
Study materials
- Refernce Books
- NCERT Solutions
- Syllabus
Send Us A Message
Latest posts

News
Navigating the Shift: A Comprehensive Guide to the Revised NCERT Class 9 Syllabus (2026-27)
Read More »
February 25, 2026
No Comments
