CHAPTER 6
How Forces Affect Motion
Questions & Solutions | Exploration | Class 9 Science
Think It Over Page 114
Think It Over
Why does a canoe move forward when the canoeist pushes water backwards with their paddle and why does it move faster when they push harder? Suppose the same canoeist uses the same paddle force in two different canoes, one empty and one carrying another passenger. In which case will the canoe move faster?
Solution
By Newton's third law, pushing water backward pushes the canoe forward. Pushing harder produces a larger forward force. The empty canoe (less mass) will accelerate more (F=ma) and move faster.
Threads of Curiosity
Page 115
In everyday life, the smallest forces we can directly feel are of the order of millinewtons (10⁻³ N), such as a light touch. Scientists, however, can measure forces far smaller than this, down to yoctonewtons (10⁻²⁴ N) in specialised experiments (as of 2026).
Solution
Scientists use sensitive instruments like atomic force microscopes and optical tweezers to measure extremely small forces at the atomic and subatomic level.
Page 124
As per Eq. (6.1), in Activity 6.3, doubling the force on the cart should have doubled the acceleration you measured. But in reality, you may have found the increase to be little less than a factor of two. Similarly in Activity 6.4, when you doubled the mass of the cart, the acceleration should have been halved but you might have found a slightly different value. Apart from measurement errors, the friction between the cart's wheels and the surface can lead to such differences.
Solution
Friction opposes motion, so the net force is less than the applied force. This causes the observed acceleration to be less than theoretically predicted.
Page 129
Apart from how hard one paddles, there are several other factors (drag, water currents, mass of the canoe, style of rowing, etc.) which impact the speed of a canoe.
Solution
Real-world motion is affected by multiple factors including drag, water currents, and mass, not just the applied force.
Ready to Go Beyond
Page 117
For an object being pushed, apart from the applied force and the force of friction, some other forces may also be acting on it (Fig. 6.11). One of these is the gravitational force (weight) and the other is the force exerted by the surface on which it is placed called the normal force. The weight acts in the downwards direction, whereas the normal force acts in the upward direction perpendicular to the surface. However, the two forces are balanced. Air around the object also exerts a force of friction on the box when the box moves through the air, but in many cases its magnitude is so small that it can be neglected.
Solution
Multiple forces act simultaneously. The net force determines motion. Balanced forces cancel out; unbalanced forces cause acceleration.
Page 124
The more complete form of Newton's second law is expressed in terms of momentum. The momentum of an object is defined as the product of its mass and velocity. The direction of the momentum is same as that of the velocity. Newton's second law states that the rate of change of momentum of an object is proportional to the net force and takes place in the direction in which the net force acts. Newton's second law expressed in this form is applicable to situations even where the mass of the object is not constant.
Solution
Momentum (p) = m × v. Newton's second law: F = dp/dt = rate of change of momentum. This form works even when mass changes (e.g., rockets).
Page 131
In addition to F, the external forces will be gravitational force (m₁g + m₂g) acting on the system downwards, which is balanced by the normal force (N₁ + N₂) acting on the system from the ground (Fig. 6.35).
Solution
For a system of connected objects, only external forces affect the motion of the system as a whole. Internal forces cancel out in pairs.
Activity 6.1 Page 118
Activity 6.1
Let us investigate: 1. Collect four coins of 10, one large strong rubber band and an adhesive tape. Locate horizontal surfaces of different materials. 2. Stack the four coins on top of each other and secure them together with an adhesive tape. 3. Hold the rubber band slightly stretched between your forefinger and thumb on the wooden table top. Mark points A and B at its ends. Make another mark C up to which you will stretch the rubber band. 4. Holding the ends of the rubber band at A and B, place the stack of coins near the middle. Push back the stack of coins till the rubber band is pulled back to the mark C. Then, release the stack of coins and observe its motion. Measure the distance travelled from C and record it. 5. Repeat steps 3 and 4 for laminated table top. 6. Next, repeat step 5 on a horizontal polished marble or tile floor. What conclusion do you draw from your observations?
Solution
The stack of coins travels farthest on the smoothest surface (polished marble) where friction is least, and least on rough surfaces (wooden table). Friction opposes motion and depends on the nature of surfaces in contact.
Activity 6.2 Page 119
Activity 6.2
Let us measure: 1. Take a spring balance and a wooden block. 2. Place the spring balance in a horizontal position on one of the surfaces used in Activity 6.1 and check that its scale reading is zero. Attach the wooden block to the hook of the spring balance. 3. Pull the spring balance with gradually increasing force and note down the reading on it when the block just starts moving. 4. Now repeat step 3 on the remaining three surfaces. 5. Compare the readings of the spring balance for all surfaces. Are the readings different? Is the reading smallest for the surface on which the stack of coins travelled the largest distance? Is the reading largest for which the distance travelled was the smallest?
Solution
The spring balance reading when the block just starts moving equals the force of friction. The smallest reading (least friction) corresponds to the smoothest surface (polished marble), where the coins travelled farthest. The largest reading (maximum friction) corresponds to the roughest surface (wooden table), where the coins travelled least.
Think as a Scientist
Page 120
Now, conduct a thought experiment. We do a thought experiment when the conditions required for the experiment are difficult to recreate in the real world. Suppose, you find an object and a horizontal floor having such smooth surfaces that the force of friction between them is zero. Imagine, what will happen if you repeat steps 3 and 4 of Activity 6.1 with such an object and a horizontal floor? Will the velocity of the object decrease? Will the object ever come to rest or continue moving forever?
Solution
If friction is zero, the object will continue moving forever with constant velocity (Newton's first law). It will never come to rest unless an external force acts on it.
Page 123
From our everyday experiences, you know that if a ball is pushed gently, it moves slowly starting from rest, i.e., the acceleration due to the force applied by you is small. On the other hand, a strong push results in the ball starting to move fast, i.e., a larger acceleration due to the force applied by you. So based on your experiences, you can make a hypothesis—for the same object, a larger force results in larger acceleration (or a smaller force results in smaller acceleration). Now, how can you test your hypothesis? Apart from force, does acceleration depends on any other factor? From everyday experiences, you know that with the same magnitude of force, it is easier to set lighter objects in motion than heavier ones. This leads to a second hypothesis, that for the same force, a smaller mass has a larger acceleration (or a larger mass has a smaller acceleration). Now how can you test your second hypothesis?
Solution
Use Activity 6.3 to test the first hypothesis (vary force, keep mass constant). Use Activity 6.4 to test the second hypothesis (vary mass, keep force constant).
Meet a Scientist
Page 120 - Galileo & Newton
In ancient times, it was well recognised that a force was required to move a stationary object or to stop a moving object. But was a force required to keep an object moving with a constant velocity? For ages, it was mistakenly thought that a force was indeed required to maintain an object in such a motion. It was only in the 17th century that Galileo Galilei argued through a series of thought experiments that if a body moves along a horizontal plane and all impediments to its motion are removed, it will continue to move indefinitely. Isaac Newton used the word 'inertia' to describe the tendency of objects to resist change in their state of rest or uniform motion, and used this idea to frame his first law of motion. Along with this, Newton presented two more laws of motion in 1687. The formulation of these three laws of motion was a defining moment in the history of science. The unit of force is named after Newton. Remember that when a unit is named after a person, its full form begins with the small case (newton and not Newton) while its symbol is capitalised (N and not n).
Solution
Galileo's thought experiments and Newton's laws established that force is not needed to maintain motion, only to change motion (accelerate).
Page 122 - Activity 6.3 & 6.4
These activities are recommended to be performed as classroom group activities facilitated by the teacher. (Demonstration activities to show relationship between force, mass, and acceleration.)
Solution
These activities experimentally demonstrate Newton's second law: F = ma.
Page 128 - Activity 6.5, 6.6, 6.7
Activities to demonstrate Newton's third law of motion.
Solution
For every action, there is an equal and opposite reaction. Forces always occur in pairs acting on different bodies.
Page 129 - Rocket launching
A rocket moves in a similar manner. Its engine produces gas and expels it in the downward direction, which in turn exerts an equal and opposite force on the rocket in the upward direction. This force on the rocket in the upward direction is larger than the weight of the rocket, so the net force is in the upward direction and the rocket lifts off.
Solution
Rocket propulsion is based on Newton's third law: action (exhaust gases downward), reaction (rocket upward).
Page 132 - Activity 6.8
A person is exerting a force on a moving box in the forward direction which is equal to the force of friction acting between the bottom surface of the box and the floor. Will the box continue moving or will it come to rest after some time?
Solution
The net force is zero, so the box will continue moving with constant velocity (Newton's first law).
Bridging Science and Society
Page 125
For a similar reason, airbags are provided in vehicles (Fig. 6.19). In the event of a collision and the vehicle coming to an abrupt halt, the airbag inflates quickly into a soft compressible cushion. Instead of directly hitting the hard steering wheel or dashboard, the passenger's head and chest push into the bag, and the time over which the hitting occurs increases. Smaller acceleration means a reduced force exerted on the person, thereby lowering the risk of serious injuries, particularly when combined with the seat belt usage.
Solution
Airbags increase the time of impact, reducing deceleration and thus the force on passengers (F = ma, smaller a means smaller F).
Page 127
While walking or running when you push the ground backwards with your foot, i.e., when your foot tries to slide backwards, the force of friction acts in the forward direction. Had there been no force of friction, your foot would have slipped backwards while attempting to push the ground and you would have fallen down. Grooves are made on the soles of footwear to increase the force of friction between the floor and soles. Similarly, treads on tyres of vehicles help increase the force of friction between the tyres and the road. You can now understand, why it is difficult to walk on wet polished floors or ice, or why it is risky to drive on roads covered with water or snow.
Solution
Friction is essential for walking and driving. Grooves and treads increase friction, preventing slipping. Wet/icy surfaces reduce friction, making movement difficult.
Activity 6.3 & 6.4 Pages 122-123
Activity 6.3 & 6.4
Demonstration activities to investigate the relationship between force, mass, and acceleration using a cart, pulley system, and weights.
Solution
These activities demonstrate that acceleration is directly proportional to net force and inversely proportional to mass (Newton's second law: F = ma).
Activities 6.5, 6.6, 6.7 Pages 127-129
Activity 6.5
Sit on a chair with wheels and push a table. What happens to you?
Solution
The chair moves in the opposite direction — action and reaction are equal and opposite (Newton's third law).
Activity 6.6
Take two identical spring balances connected together. Pull them in opposite directions. What do the readings show?
Solution
Both spring balances show the same reading, indicating equal and opposite forces.
Activity 6.7
Inflate a balloon, attach a straw, pass a thread through it, and release the balloon. Observe the motion.
Solution
Air rushing out exerts a force on the balloon in the opposite direction, moving it forward — Newton's third law.
Pause and Ponder
Page 117 (Q1)
A weightlifter lifts a barbell (Fig. 6.8). List two forces that are acting on the barbell. Are these forces balanced if the weightlifter keeps the barbell steady?
Solution
Gravitational force (downward) and upward force by weightlifter. Yes, they are balanced (net force = 0).
Page 117 (Q2)
Two players R and S are participating in an arm-wrestling match (Fig. 6.9). At the instant, when the arms tilt to the front direction (out of the page towards you), are the forces exerted by the players balanced? If not, which player exerted the larger force?
Solution
Forces are not balanced. The player towards whom the arms tilt exerted the larger force.
Page 121 (Q3)
An object is moving with a constant velocity. Is there a net force acting upon it?
Solution
No, net force is zero (Newton's first law).
Page 121 (Q4)
Suppose, no net force is acting on an object. Which of the following situations are possible? (i) Object remains at rest if at rest. (ii) Object keeps moving with a constant velocity if already moving. (iii) Object is moving with a constant acceleration.
Solution
Options (i) and (ii) are possible. Option (iii) is not possible because acceleration requires net force.
Page 121 (Q5)
In the real world, it is difficult to find a situation where no forces are acting on an object. But by applying additional forces, a condition can be achieved where the net force on the object is zero. Explain with the help of an example.
Solution
Example: A book on a table. Gravitational force pulls it down, normal force from table pushes it up. These are equal and opposite, so net force is zero.
Page 126 (Q6)
A toy car of mass 100 g is moving with a constant velocity of 0.5 m/s. What is the net force acting on the toy car?
Solution
Net force = 0 N (constant velocity means zero acceleration, so F = ma = 0).
Page 126 (Q7)
Two children of different masses are sitting on identical swings. To impart identical initial acceleration, for which child would you require to apply a larger force? Explain why.
Solution
Larger force is needed for the child with larger mass because F = ma (greater m requires greater F for same a).
Page 126 (Q8)
How are glass items packed for transportation using a bubble wrap or hay protected from damage?
Solution
Bubble wrap increases the time of impact during a fall, reducing acceleration and thus force on glass items (F = ma, smaller a means smaller F).
END-OF-CHAPTER EXERCISES Pages 132-134
1.
Using a horizontal force F, a table is moved across the floor at a constant velocity. How much is the frictional force exerted by the floor on the table?
Solution
Frictional force = F (since constant velocity means net force = 0, so friction equals applied force).
2.
For a ball moving on a smooth frictionless surface, choose the appropriate option: (i) If no net force is applied on the ball, the velocity of the ball will remain the same/increase/decrease. (ii) If a net force is applied on the ball in the direction of its motion, the magnitude of the velocity of the ball will remain the same/increase/decrease. (iii) If a net force is applied on the ball in a direction opposite to the direction of its motion, the magnitude of the velocity of the ball will remain the same/increase/decrease.
Solution
(i) remain the same, (ii) increase, (iii) decrease.
3.
Two blocks P and Q on a smooth horizontal surface are shown in Fig. 6.36a and Fig. 6.36b. Two forces of magnitudes 4 N and 5 N are acting in opposite directions on block P, while block Q is moving with a constant velocity. Which of the following statement is correct? (i) P experiences a net force and Q does not experience a net force. (ii) P does not experience a net force and Q experiences a net force. (iii) Both P and Q experience a net force. (iv) Neither P nor Q experiences a net force.
Solution
Option (i) is correct: Net force on P = 1 N, net force on Q = 0 (constant velocity).
4.
While practising for the snake boat race (Vallum kalli in Kerala), 100 oarsmen are rowing a boat together. Out of these, 95 row backwards to propel the boat forward. But by mistake, 5 oarsmen row in the opposite direction. If each oarsman applies a horizontal force of 200 N, what is the net force on the snake boat? (Ignore drag forces, air friction, etc.)
Solution
Forward force = 95 × 200 = 19,000 N. Backward force = 5 × 200 = 1,000 N. Net force = 19,000 - 1,000 = 18,000 N forward.
5.
When a net force acts on an object, we observe that the object accelerates: (i) opposite to the direction of force, with acceleration proportional to the force. (ii) opposite to the direction of force, with acceleration proportional to the mass. (iii) in the direction of force, with acceleration inversely proportional to the force. (iv) in the direction of force, with acceleration proportional to the force.
Solution
Option (iv) is correct: acceleration is in the direction of net force and is proportional to the force (F = ma).
6.
The position-time graph for four objects A, B, C and D moving along a straight line are given in Fig. 6.37. A net force acts on: (i) Object A (ii) Object B (iii) Object C (iv) Object D
Solution
Net force acts on objects with curved position-time graphs (changing velocity/acceleration).
7.
A sailor jumps out from a small boat to the shore (Fig. 6.38). As the sailor jumps forward, will the boat move? If yes, in which direction and why.
Solution
Yes, the boat moves backward due to Newton's third law — action (sailor jumps forward), reaction (boat moves backward).
8.
During a high jump event, a landing mat or sand bed is placed for the athlete to fall upon (Fig. 6.39). Explain the reason behind it.
Solution
Landing mat increases the time of impact, reducing deceleration and thus the force on the athlete (F = ma, smaller a means smaller F).
9.
A hand cart loaded with vegetables collides with an identical but empty hand cart. During the collision: (i) the loaded cart exerts a force of larger magnitude on the empty cart. (ii) the empty cart exerts a force of larger magnitude on the loaded cart. (iii) neither cart exerts a force on the other. (iv) the loaded cart and the empty cart, both exert an equal magnitude of force on each other.
Solution
Option (iv) is correct: By Newton's third law, forces are equal in magnitude and opposite in direction.
10.
The acceleration-mass graph for the acceleration produced by a force on objects of different masses is plotted in Fig. 6.40. Plot the force-mass graph for this case.
Solution
Force = constant = m × a. Since a ∝ 1/m, F remains constant. Force-mass graph is a horizontal line.
11.
The velocity-time graph of an object of mass 10 kg moving along a straight line is shown in Fig. 6.41. Calculate the force acting on the object by using the graph.
Solution
F = m × a. From graph, a = slope = (10-0)/(4-0) = 2.5 m/s². F = 10 × 2.5 = 25 N.
12.
A bullet of mass 50 g moving with a speed of 100 m/s enters a heavy stationary wooden block and stops after penetrating a distance of 50 cm. Estimate the stopping force acting on the bullet (assume that the bullet undergoes constant acceleration within the block).
Solution
v² = u² + 2as → 0 = 100² + 2 × a × 0.5 → a = -10000 m/s². F = m × a = 0.05 × (-10000) = -500 N (magnitude 500 N opposite to motion).
13.
An ace footballer converted a penalty shot by kicking the football with a speed of 108 km/h. The estimated force they imparted was 800 N. The mass of the football was 0.4 kg. Calculate the time of contact between their foot and the ball.
Solution
u = 0, v = 108 km/h = 30 m/s. F = ma = m(v-u)/t → 800 = 0.4 × 30 / t → t = 12/800 = 0.015 s.
14.
An object of mass 2 kg moving with a constant velocity of 10 m/s encounters a rough patch where the force of friction on the object is 7 N. At the same time, an additional constant force of 3 N opposing the motion is applied on the object. After entering the rough patch, how much distance does the object travel before coming to rest?
Solution
Net opposing force = 7 + 3 = 10 N. a = F/m = -10/2 = -5 m/s². v² = u² + 2as → 0 = 100 + 2(-5)s → s = 100/10 = 10 m.
15.
A tractor pulls a harrow (a ploughing tool) of mass m₁ with a net force F resulting in an acceleration of a₁. The same tractor pulls a trolley of mass m₂ with a force F producing an acceleration of a₂. If the tractor now pulls the trolley with the harrow placed on it (with the same force F), then obtain an expression for the resulting acceleration in terms of a₁ and a₂. Ignore friction.
Solution
F = m₁a₁, F = m₂a₂. Total mass = m₁ + m₂. a = F/(m₁+m₂) = F/(F/a₁ + F/a₂) = 1/(1/a₁ + 1/a₂) = a₁a₂/(a₁ + a₂).
16.
When the pole of a bar magnet is brought close to a magnetic compass, the bar magnet and the compass needle (which is also a magnet) exert a magnetic force on each other. As per Newton's third law of motion, both the forces are equal in magnitude and opposite in direction. However, the compass needle moves, whereas the bar magnet does not move (Fig. 6.42). Explain why.
Solution
The compass needle has very small mass compared to the bar magnet. The same force produces a large acceleration (a = F/m) in the needle, but negligible acceleration in the heavy magnet.
Chapter Summary
- Force is a push or pull that can change an object's state of rest or motion.
- Balanced forces do not change motion; unbalanced forces cause acceleration.
- Friction opposes motion and depends on the nature of surfaces in contact.
- Newton's first law: An object remains at rest or in uniform motion unless acted upon by a net force.
- Newton's second law: F = ma (force = mass × acceleration).
- Newton's third law: Every action has an equal and opposite reaction.
- Momentum = mass × velocity. Rate of change of momentum equals net force.
- Airbags, landing mats, and bubble wrap increase impact time to reduce force.
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Chapter 6: How Forces Affect Motion — All Questions with Solutions
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