NCERT Soultions

Class 9 Maths, NCERT – Chapter 7: Triangles Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 6: Lines And Angles Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 5: Euclid’s Geometry Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 4: Linear Equations In Two Variables Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 3: Coordinate Geometry Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 2: Polynomials Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 1: Number Systems Powered By EmbedPress

Exercise 8.1 Question 1: In (ΔABC) right angled at (B, AB = 24 cm, BC = 7 m). Determine (i) sin A, cos A (ii) sin C, cos C Answer:  Applying Pythagoras theorem for (ΔABC), we obtain (AC^2 = AB^2  + BC^2) (=(24cm)^2+(7cm)^2) (=(567+49)cm^2) (=625cm^2) (∴AC=sqrt{625}cm=25cm) (i)  (Sin A=frac{Sidespace oppositespace toangle A}{Hypotenuse}=frac{BC}{AC}) (=frac{7}{25}) (cos A=frac{Sidespace

6.1 Question 1: Fill in the blanks using correct word given in the brackets:− (i) All circles are __________. (congruent, similar) (ii) All squares are __________. (similar, congruent) (iii) All __________ triangles are similar. (isosceles, equilateral) (iv) Two polygons of the same number of sides are similar, if (a) their corresponding angles are __________ and

Exercise 7.1 Question 1: Find the distance between the following pairs of points: (i) (2, 3), (4, 1) (ii) (-5, 7), (-1, 3) (iii) (a, b), (-a, -b) Answer: (i) Distance between the two points is given by (sqrt {(x_1-x_2)^2+(y_1-y_2)^2}) Therefore, dustance between (2, 3) and (4, 1) is given by (l=sqrt{(2-4)^2+(3-1)^2=sqrt{(-2)^2+(2)^2}}) (=sqrt{4+4}=sqrt8=2sqrt2) (ii) Distance between