NCERT Solutions for Maths Class 10 Chapter 8
Exercise 8.1 Question 1: In (ΔABC) right angled at (B, AB = 24 cm, BC = 7 m). Determine (i) sin A, cos A (ii) sin C, cos C Answer: Applying Pythagoras theorem for (ΔABC), we obtain (AC^2 = AB^2 + BC^2) (=(24cm)^2+(7cm)^2) (=(567+49)cm^2) (=625cm^2) (∴AC=sqrt{625}cm=25cm) (i) (Sin A=frac{Sidespace oppositespace toangle A}{Hypotenuse}=frac{BC}{AC}) (=frac{7}{25}) (cos A=frac{Sidespace […]
NCERT Solutions for Maths Class 10 Chapter 8 Read Post »