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Class 9 Maths, NCERT – Chapter 9: Circles Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 8: Quadrilaterals Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 7: Triangles Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 6: Lines And Angles Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 5: Euclid’s Geometry Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 4: Linear Equations In Two Variables Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 3: Coordinate Geometry Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 2: Polynomials Powered By EmbedPress

Class 9 Maths, NCERT – Chapter 1: Number Systems Powered By EmbedPress

Exercise 8.1 Question 1: In (ΔABC) right angled at (B, AB = 24 cm, BC = 7 m). Determine (i) sin A, cos A (ii) sin C, cos C Answer:  Applying Pythagoras theorem for (ΔABC), we obtain (AC^2 = AB^2  + BC^2) (=(24cm)^2+(7cm)^2) (=(567+49)cm^2) (=625cm^2) (∴AC=sqrt{625}cm=25cm) (i)  (Sin A=frac{Sidespace oppositespace toangle A}{Hypotenuse}=frac{BC}{AC}) (=frac{7}{25}) (cos A=frac{Sidespace